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3 years ago

How do i answer this?

Mathematics

1 answer:

balandron [24]3 years ago

6 0

1) CBD 2) HJK 3) PQR

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Need help with this

stira [4]

Answer: 5,356 is the right asnwer

Step-by-step explanation: I did the paper hope this helps :)

6 0

3 years ago

The area of a regular hexagon is 14.96 cm2. What is the perimeter of the hexagon? A. 1.2 space c m B. 1.2 square root of 3 space

victus00 [196]

Answer:

14.4 cm

Step-by-step explanation:

The formula for the area of a regular hexagon in terms of its side length s is ...

... A = (3√3)/2·s²

Then the side length is ...

... s = √(2A/(3√3))

and the perimeter is ...

... P = 6s = √(8A√3)

For your area, this is ...

... P = √(8·14.96·√3) ≈ √207.292 ≈ 14.4 . . . . cm

7 0

3 years ago

Read 2 more answers

What’s the slope of the line?

Alexeev081 [22]

Answer:

4/3

Step-by-step explanation:

You use Rise over Run.

It runs 3 blocks to the left (+).

It rises 4 blocks up (+).

6 0

3 years ago

Read 2 more answers

Can someone help - wrote an equation of the line in slope intercept form

adoni [48]

Answer:

y=-2x+8

Step-by-step explanation:

Hope this helps!

5 0

3 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

3 years ago