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Bess [88]
3 years ago
9

How do i answer this?

Mathematics
1 answer:
balandron [24]3 years ago
6 0

1) CBD 2) HJK 3) PQR

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\displaystyle\\|\Omega|=\binom{16}{2}=\dfrac{16!}{2!14!}=\dfrac{15\cdot16}{2}=120\\|A|=\binom{5}{2}=\dfrac{5!}{2!3!}=\dfrac{4\cdot5}{2}=10\\\\P(A)=\dfrac{10}{120}=\dfrac{1}{12}\approx0.083

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