Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
Answer:
1. 35
2. 145
3. 55
4. 90
5. 145
Step-by-step explanation:
1. 35: angle 1 and 2 are a linear pair (meaning it is in one line and adds to 180). Since we know angle 2 is 145, ∠1 = 180 - 145
∠1 = 35
2. 145: ∠7 = ∠2 because they are alternate angles and alternate angles are equal
3. 55: ∠7 = ∠5 + ∠4 because vertically opposite angles are equal. We know that ∠5 = 90, hence ∠4 would equal 145 - 90 = 55
4. ∠5 = 90. It is given
5. 145: ∠9 = ∠2 because they are vertically opposite
Answer:
f
Step-by-step explanation:
fgbdf
You simplefie them and get 1/2 for 4/8
2/3 for 8/12
3/4 cannot be somplified
Hey
Here it is!!
8x+1=5
8x=4
x= 4/8
x=1/2
