$\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)$

3 0

3 years ago

Function 1 is defined by the equation y=2x+10

cricket20 [7]

Answer:

C. The functions have the same y-intercept

Step-by-step explanation:

In slope intercept form, y = mx + b, b represents the y-intercept, and in the first function the y-intercept is 10.

The y-intercept is when x = 0, and in the chart, when x equals 0, y equals 10.

10 = 10, so they have the same y-intercept.

5 0

3 years ago

Is 5 in the solution set of x+3>8

Irina-Kira [14]

Answer:

It 5 would not be x

Step-by-step explanation:

If 5 was x, then it would be equivalent, because 5+3 = 8. I hope this helped.

8 0

3 years ago

Read 2 more answers

Please help im having problem

jeka94

Answer:

Step-by-step explanation:

Do i need to explain ??????

3 0

3 years ago