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4 years ago

Help me please please

Mathematics

1 answer:

Ivan4 years ago

5 0

Answer: 11

============================================

Explanation:

Point C is the circumcenter of triangle PQR. This means that we can draw a circle centered at C that goes through points P, Q and R at the same time. This circle has a special name: circumcircle.

The segments PC, RC and QC are all radii, so they are the same length. Pick two of the given expressions and set them equal to one another. Then solve for x

I'm going to pick the expressions for PC and RC

PC = RC
3x+7 = 5x-15
5x-3x = 7+15
2x = 22
x = 22/2
x = 11

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A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the

Katena32 [7]

Answer:

Stabilizer with area = 14 cm².

Step-by-step explanation:

Area of the wing = 101.25 cm²

Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.

1/6 of the area of wing = $\frac{1}{6} \times 101.25 = 16.875$

1/8 of the area of wing = $\frac{1}{8} \times 101.25 = 12.656$

This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²

Therefore, area of a good stabilizer design from the given options would be 14 cm²

5 0

4 years ago

In right triangle XYZ, the right angle is located at vertex Y. The length of line segment XY is 12.4 cm. The length of line segm

Advocard [28]

Answer:

The measure of angle YZX is 39.4°.

Step-by-step explanation:

Given information: ΔXYZ is a right angled triangle, ∠Y=90°, XY=12.4 cm, YZ=15.1 cm.

In a right angled triangle,

$\tan \theta = \frac{opposite}{adjacent}$

In triangle XYZ,

$\tan (\angle YZX) = \frac{XY}{YZ}$

$\tan (\angle YZX) = \frac{12.4}{15.1}$

Taking tan⁻¹ on both sides.

$\angle YZX =\tan^{-1} (\frac{12.4}{15.1})$

$\angle YZX =39.3925680393$

$\angle YZX \approx 39.4^{\circ}$

Therefore the measure of angle YZX is 39.4°.

8 0

4 years ago

A ball is thrown from the top row of seats in a stadium. The function h(t)=-16t^2+64t+80 gives the height, in feet, of the ball

Wewaii [24]

Answer:

<h3>5 seccs</h3>

Step-by-step explanation:

Given the modeled function of the height expressed as;

h(t)=-16t^2+64t+80

The ball hits the ground when h(t) = 0 (when the height is zero)

Substitute into the function and find t;

0 =-16t^2+64t+80

divide through by -16

0 = t²-4t-5

Factorize;

t²-4t-5 = 0

t²-5t+t-5 = 0

t(t-5)+1(t-5) = 0

(t+1)(t-5) = 0

t + 1 = 0 and t-5 = 0

t = -1 and t = 5

Time can't be negative

Hence it will take the ball 5secs before it hits the ground

7 0

3 years ago

In the equation -3(y-2)2/3+29=-19, the values of y are

Elodia [21]

See attached explanation.: Answer: y=26 or

Step-by-step.(−3(y−2))(2)3+29=−19
Step 1: Simplify both sides of the equation.(−3(y−2))(2)3+29=−19Simplify: −2y+4+29=−19 (Distribute)(−2y)+(4+29)=−19 (Combine Like Terms)−2y+33=−19−2y+33=−19

Step 2: Subtract 33 from both sides.−2y+33−33=−19−33−2y=−52

Step 3: Divide both sides by -2.−2y−2=−52−2y=26Answer: y=26

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4 years ago

Find DE (trigonometry) Show work pls

Ksju [112]

Answer:

Step-by-step explanation:

tan61=FD/24

FD=24tan61

tan19=DE/FD

DE=FDtan19, since FD=24tan61

DE=(24tan61)(tan19) (exact)

DE=14.9 units (rounded to nearst tenth)

Though they might round to 15 units...

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3 years ago