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photoshop1234 [79]

3 years ago

12

Pitágoras filósofo matemático griego biblio entre los años 500 8496 antes de Cristo A qué edad murió y cuántos años hace que mur

ió

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

if you can transfer to englis i may be able to help

Step-by-step explanation:

You might be interested in

Explanation A random sample of 100 observations from a normally distributed population possesses a mean equal to 83.2 and a stan

Olenka [21]

Answer:

The 95% confidence interval would be given by (81.933;84.467)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=83.2$ represent the sample mean

$\mu$ population mean (variable of interest)

s=6.4 represent the sample standard deviation

n=100 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=100-1=99$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that $t_{\alpha/2}=1.98$

Now we have everything in order to replace into formula (1):

$83.2-1.98\frac{6.4}{\sqrt{100}}=81.933$

$83.2+1.98\frac{6.4}{\sqrt{100}}=84.467$

So on this case the 95% confidence interval would be given by (81.933;84.467)

7 0

3 years ago

I need help solving the second part. Give me help or answer.

alex41 [277]

I think the answer is 273

You divide 31% by any of the other percentages (like for example, 25%) and then divide 93 by whatever you got as your answer (31 divided by 25 was 1.24, so I divided 93 by 1.24 to get 75) then repeat that with the other percentages and add them all up.

3 0

3 years ago

Write the equation of the line in slope-intercept form.

svet-max [94.6K]

Answer:

y=4b-5m

Step-by-step explanation:

4 0

3 years ago

Hello there ^ _ ^ <br><br> Can you help me please ? Please explain how you find the answer. Thanks!

ziro4ka [17]

It's C because for the perpendicular line, you need to construct cross points to draw it through.

- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.

8 0

4 years ago

A high school has 36 players on the football team. the summary of the players' weights is given in the box plot. what is the int

Komok [63]

The interquartile range of the players' weights = 48 pounds.

The boxplot attached to this question is missing. It was obtained online and is attached to this solution of the question.

It should be noted that the following is true for a boxplot.

A box plot gives a visual representation of the distribution of the data, showing where most values lie and those values that greatly differ from the rest, called outliers.

The elements of the box plot are described thus;

The bottom side of the box represents the first quartile, and the top side, the third quartile. Therefore, the width of the central box represents the inter-quartile range.

The horizontal line inside the box is the median.

The lines extending from the box reach out to the minimum and the maximum values in the data set, as long as these values are not outliers. The ends of the whiskers are marked by two shorter horizontal lines.

Variables in the dataset, higher than Q3+(1.5×IQR) or lower than Q1-(1.5×IQR) are considered outliers and are usually shown using dots above the top whisker or below the bottom whisker.

So, it is evident that for this question,

First quartile = 174 pounds

Third quartile = 222 pounds

Inter Quartile Range = (Third quartile) - (First quartile)

= 222 - 174

= 48 pounds.

To know more about "interquartile"

Refer this link:

brainly.com/question/16988652

#SPJ4

6 0

2 years ago