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3 years ago

What is the solution to the equation below round your answer to two decimal places 5+6*log2x=14

Mathematics

1 answer:

Artemon [7]3 years ago

6 0

9514 1404 393

Answer:

2.83 for log2(x)

15.81 for log(2x)

Step-by-step explanation:

We can get the log function by itself by subtracting the constant and dividing by the coefficient.

5 +6·log2x = 14

6·log2x = 9 . . . . . . . subtract 5

log2x = 1.5 . . . . . . . divide by 6

At this point, we're not sure what is meant by log2x.

log₂(x) = 1.5 ⇒ x = 2^1.5 ≈ 2.83

log(2x) = 1.5 ⇒ x = (10^1.5)/2 ≈ 15.81

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3 years ago

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3 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

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