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Nadusha1986 [10]
2 years ago
15

Mr. Johnson's math class has twice as many students as Mrs. Jones' math class.

Mathematics
2 answers:
kirill [66]2 years ago
8 0

Answer: 4x54=216

Step-by-step explanation:

Well you don’t need to count in mr smiths math class because all the classes has 54 so um I did 4x54 hoped this helped :)

Rudiy272 years ago
8 0

Answer:

Mr Smith: 24

Mr Johnson: 20

Mrs Jones: 10

24+20+10=54

Step-by-step explanation:

So I took a random number, and that number was 24.

I took 24 and put at as my testing in Smith's class.

If Mr. Smith had 24 students then, (x-4=Mr Johnson's class) Mr Johnson has 20 students, and half of that would be the amount of students in Mrs Jones class, so that equals 10.

J = Jones

Jo = Johnson

S = Smith

Finally  S+Jo+J=54

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anastassius [24]

Answer:

x =-24

Step-by-step explanation:

Given

(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3

Required

Solve for x

(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3

Open all brackets

\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3

\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3

\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3

\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3

Collect like terms

\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8

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Solve fraction

\frac{2-1}{6}x =-4

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8 0
3 years ago
What survival rate in the 10th year would make the average rate of loss over the 10-year period equal to 38.0%?
Morgarella [4.7K]

Answer: 63%

Step-by-step explanation:

First find the rate of loss that would cause the average rate of loss over the 10-year period equal to 38.0%.

Assume that rate is x.

38 = (36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x) / 10

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= 1 - rate of loss

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2 years ago
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-213

Step-by-step explanation:

3|3-5|^2-(-15)^2

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3 0
3 years ago
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