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Nadusha1986 [10]
3 years ago
15

Mr. Johnson's math class has twice as many students as Mrs. Jones' math class.

Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer: 4x54=216

Step-by-step explanation:

Well you don’t need to count in mr smiths math class because all the classes has 54 so um I did 4x54 hoped this helped :)

Rudiy273 years ago
8 0

Answer:

Mr Smith: 24

Mr Johnson: 20

Mrs Jones: 10

24+20+10=54

Step-by-step explanation:

So I took a random number, and that number was 24.

I took 24 and put at as my testing in Smith's class.

If Mr. Smith had 24 students then, (x-4=Mr Johnson's class) Mr Johnson has 20 students, and half of that would be the amount of students in Mrs Jones class, so that equals 10.

J = Jones

Jo = Johnson

S = Smith

Finally  S+Jo+J=54

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I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help
VMariaS [17]

Answer: a) 8.779 years

               b) 8.664 years

<u>Step-by-step explanation:</u>

a)

A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}

  • A: accumulated amount (balance)
  • P: principal amount (original/initial investment)
  • r: interest rate (convert to a decimal)
  • n: number of times compounded per year
  • t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}

b)  

A=Pe^{rt}

1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}

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3 years ago
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