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3 years ago

1. Mercury is most often obtained by roasting cinnabar (HgS). How many grams of cinnabar

Chemistry

1 answer:

Flauer [41]3 years ago

5 0

Answer:

191.4 grams of cinnabar are required to obtain 165 grams of mercury.

Explanation:

The balanced reaction is:

HgS + O₂ ⇒ Hg + SO₂

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

HgS: 1 mole
O₂: 1 mole
Hg: 1 mole
SO₂: 1 mole

Being the molar mass of each compound:

HgS: 232g/mole
O₂: 32 g/mole
Hg: 200 g/mole
SO₂: 64 g/mole

the following mass amounts of each compound participate in the reaction:

HgS: 1 mole* 232 g/mole= 232 g
O₂: 1 mole* 32 g/mole= 32 g
Hg: 1 mole* 200 g/mole= 200 g
SO₂: 1 mole* 64 g/mole= 64 g

Then you can apply the following rule of three: if by stoichiometry 200 grams of Hg are formed from 232 grams of HgS , 165 grams of Hg are formed from how many grams of HgS?

$mass of HgS=\frac{165 grams of Hg*232 grams of HgS}{200 grams of Hg }$

mass of HgS= 191.4 grams

<em><u>191.4 grams of cinnabar are required to obtain 165 grams of mercury.</u></em>

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