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Gekata [30.6K]
3 years ago
7

imagine you have four food dyes to test A, B, C and D imagine that you are going to investigate which food dye diffuses more qui

ckly a- which variable will you change? b- which variable will you measure? how will you do this?
Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

You will change which food dye is used. You will measure how quickly the dyes diffuse. You could use a timer to see how long the dye takes to completely diffuse.

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In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the
notka56 [123]

Answer:

P_T=112.4torr

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

P_{H_2}=x_{H_2}*P_T

And can be solved for the total pressure as follows:

P_T=\frac{P_{H_2}}{x_{H_2}}

However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:

x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667

Then, we can plug in to obtain the total pressure:

P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr

Regards!

4 0
2 years ago
What chemical change is magnetizing steel
labwork [276]
Magnetizing steel is a physical change, not a chemical change.
4 0
2 years ago
A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

q_{released}=q_{absorbed}\\&#10;q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T

The given mass of calorimeter has been, m_{calorimeter}=1350\;\rm g

The specific heat of the calorimeter has been, c_{calorimeter}=5.82\;\rm J/g^\circ C

The change in temperature of the calorimeter has been, \Delta T=2.87^\circ \rm C

Substituting the values for heat released:

q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0
2 years ago
ASAP I AM GIVING BRAINLIEST PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPP
faust18 [17]

Answer:

D) It has a different unit than atomic mass.

4 0
3 years ago
Formation of ionic bond is affected by​
Alina [70]

Answer:

Ionization energy, electronegativity, and lattice energy are the factors that influence the formation of ionic bonds of elements.

6 0
3 years ago
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