Answer:
Mass of water produced= 1.8 g
Explanation:
Given data:
Mass of water produced = ?
Mass of butane = 1.36 g
Mass of oxygen = excess
Solution:
Chemical equation:
2C₄H₁₀ +13 O₂ → 8CO₂ + 10H₂O
Number of moles of butane:
Number of moles = mass/molar mass
Number of moles = 1.36 g/ 58.12 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of butane with water.
C₄H₁₀ : H₂O
2 : 10
0.02 : 10/2×0.02 = 0.1 mol
Mass of water produced:
Mass = molar mass × molar mass
Mass = 0.1 mol × 18 g/mol
Mass = 1.8 g
Answer:
No it is not balanced
Explanation:
CaCl2 + 2NaHCO3 → CO2 + CaCO3 + H2O + 2NaCl
Hope this helps
Answer:
-1, -2
Explanation:
West is left south is down east is right
Given what we know, we can confirm that the type of van der Waals interactions that occur between molecules of O2, SCl2, and CH4 in liquids of these substances are the presence of <u>London dispersion forces</u>.
<h3>What are London dispersion forces?</h3>
- They are a force of attraction between atoms.
- They are generated by electrostatic attraction.
- These forces are common between atoms in close proximity and occur often when compounds have a symmetrical distribution of atoms.
- They are generated by the formation of temporary dipoles.
Therefore, given the symmetry of the atoms disposition in these compounds and the temporary dipoles generated by the atoms being in close proximity, we can confirm that the van der Waals forces present in each compound are London dispersion forces.
To learn more about van deer Waals forces visit:
brainly.com/question/13201335?referrer=searchResults
<u>Answer</u><u>:</u>
Hydrocarbon and oxygen
<u>Explanation</u><u>:</u>
"a substance reacts with oxygen gas, it must involve O² as one of the reactants."
Using this, we can confirm Hydrocarbon and oxygen is a valid one.
