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Sunny_sXe [5.5K]
3 years ago
8

PLEASE HELP ME PLEASE! BRAINLEST ​

Physics
1 answer:
Vadim26 [7]3 years ago
6 0

Answer:

10kg

Explanation:

Weight is "how much does gravity drag this down".

Mass is "how much matter is there here".

The relation is:

F_g = mg

where F_g is the weight, m is the mass and g is the gravitational acceleration (roughly equal to 10N/kg on Earth).

From the task we know that:

F_g = 100N\\g = 10\frac{N}{kg}

So let's input it into the relation:

100N = m\cdot 10\frac{N}{kg}\\10N = m \cdot 1\frac{N}{kg}\\10N \cdot \frac{kg}{N} = m\\~\\m = 10kg

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Which property of light is a constant in a vacuum?
faust18 [17]

Answer:

La velocidad de la luz en el vacío es una constante universal con el valor de 299 792 458 m/s (186 282,397 mi/s),​​aunque suele aproximarse a 3·108 m/s. Se simboliza con la letra c, proveniente del latín celéritās (en español, celeridad o rapidez).

¿Cuál es la consecuencia que a velocidad de la luz sea constante?

Respuesta. En modificaciones del vacío más sutiles, como espacios curvos, efecto Casimir, poblaciones térmicas o presencia de campos externos, la velocidad de la luz depende de la densidad de energía de ese vacío.

5 0
3 years ago
A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

\rho = \dfrac{m}{V}

where m is the mass and V is the volume.

m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

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3 years ago
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As a factor of production, how is capital created?
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Read 2 more answers
A student holds a bike wheel and starts it spinning with an initial angular speed of 9.0 rotations per second. The wheel is subj
KATRIN_1 [288]

Answer:

\Delta t = 8 s

Explanation:

As we know that the angular acceleration of the wheel due to friction is constant

so we can use kinematics

\theta = \omega_i t + \frac{1}{2}\alpha t^2

so we have

(65 \times 2\pi) = (2\pi \times 9)(10) + \frac{1}{2}(\alpha)(10^2)

130\pi = 180\pi + 50 \alpha

\alpha = -\pi rad/s^2

now time required to completely stop the wheel is given as

\omega_f = \omega_i + \alpha t

0 = (2\pi \times 9) + (-\pi) t

t = 18 s

now time required to stop the wheel is given as

\Delta t = 18 - 10

\Delta t = 8 s

6 0
3 years ago
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