Answer:
The read will be 20.9[C]![x=\frac{(y-y_{1} )}{(y_{2} -y_{1} )}*(x_{2}-x_{1})+y_{1}\\ x=\frac{(18-0 )}{(95 -0 )}*(100-2)+2\\\\x= 20.9[C]](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B%28y-y_%7B1%7D%20%29%7D%7B%28y_%7B2%7D%20-y_%7B1%7D%20%29%7D%2A%28x_%7B2%7D-x_%7B1%7D%29%2By_%7B1%7D%5C%5C%20%20x%3D%5Cfrac%7B%2818-0%20%29%7D%7B%2895%20-0%20%29%7D%2A%28100-2%29%2B2%5C%5C%5C%5Cx%3D%2020.9%5BC%5D)
Explanation:
This is a problem related to linear interpolation, Linear interpolation consists of tracing a line through two known points y = r (x) and calculating the intermediate values according to this line.
The equation of a known line two points (x1, y1)and (x2, y2) = (2,0) (100,95) is:
If we clear y from the equation we have:
[tex]y=\frac{(x-y_{1})}{(x_{2}-x_{1} )}*(y_{2} -y_{1} )+y_{1} \\replacing
Answer:
True. Diffusion and osmosis are forms of passive transport.
Explanation:
In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.
In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.
Answer:
Reigon 1
Explanation:
It has the higest rate of landslides currently
Answer:
i)-6.25m/s
ii)18 metres
iii)26.5 m/s or 95.4 km/hr
Explanation:
Firstly convert 90km/hr to m/s
90 × 1000/3600 = 25m/s
(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)
0 = (25)^2 + 2A(50)
0 = 625 + 100A....then moved the other value to one
-625 = 100A
Hence A = -6.25m/s^2(where the negative just tells us that its deceleration)
(ii) Firstly convert 54km/hr to m/s
In which this is 54 × 1000/3600 = 15m/s
then apply the same formula as that in (i)
0 = (15)^2 + 2(-6.25)s
-225 = -12.5s
Hence the stopping distance = 18metres
(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question
0 = u^2 + 2(-6.25)(56)
u^2 = 700
Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s
In km/hr....26.5 × 3600/1000 = 95.4 km/hr
I think it was by boat and coming from over seas
