This is false because people could use way much water
Mean for the <u>Geno Code 0</u> is average of those ten values ((-3.97)+(-3.99) +(-5.55)+ (-4.56) + (-4.51) + (-4.2 )+( -4.95) + (-4.56) + (-4 )+ (-5.68))/10= -4.597
Standard deviation formula is √((-3.97- (-4.597)2 )+(-3.99-(-4.597)2) +(-5.55-(-4.597)2)+ (-4.56-(-4.597)2) + (-4.51-(-4.597)2) + (-4.2-(-4.597) 2 )+( -4.95-(-4.597)2) + (-4.56-(-4.597)2) + (-4 -(-4.597)2)+ (-5.68-(-4.597)2))/10= √ (0.39+0.37+0.91+0.001+0.007+0.16+0.12+0.001+0.36+1.17)/10= √0.3489=0.59
Mean for the <u>Geno 1 </u>is -0.25 (calculated on the same way as for Geno 0 with different numbers) and standard deviation for Geno 1 is 0.65.
Mean for <u>Geno 2</u> is 5.241 and standard deviation is 1.038.
2.
If individual Phenotype_Value is 5.11, the corresponding genotype code is Geno code 2 since the value is in the range of values 5.241+- 1.
If individual Phenotype_Value is 5.03 the corresponding genotype code is also Geno code 2.
Since the standard deviation is used to measure the variation (dispersal) of set of data values (how close the values are to the mean value) we can conclude whether are random value is within a certain range.
Reef-building corals were
confined to relatively shallow depths because
many of these corals have microscopic algae
called zooxanthellae living inside their soft tissues.
These algae
are often important for the corals’ nutrition and
growth, but require sunlight for photosynthesis. There is no sunlight deep in the water.
They are cooler and drier than tropical rain forests. Abiotic factors, or nonliving factors, of a temperate rain forest include temperature, water, cloud cover, soil and light. These abiotic factors interact with biotic, or living factors, to form the rain forest's unique ecosystem.
