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user100 [1]
3 years ago
6

A calendar shop has 3,500 calendars. Each rack can hold 500 calendars. How many racks does the store need to use?

Mathematics
2 answers:
insens350 [35]3 years ago
7 0
About 6 racks or storage
mash [69]3 years ago
7 0

Answer:

7

Step by step explanation:

Total no of calendar s = 3,500

Capacity of one rack = 500 calendar

Total no of racks = 3,500/500 = 7

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47/24 is the exact answer
3 0
4 years ago
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Please help!!!!
Flauer [41]

The cotangent function is defined as the length of the side adjacent over the length of the side opposite.

Step-by-step explanation:

The sine of an angle is defined as the length of the side opposite over the length of the hypotenuse.

The cosine of an angle is defined as the length of the side adjacent over the length of the hypotenuse.

The tangent of an angle is defined as the length of the side opposite over the length of the side adjacent.

The cotangent function is defined as the length of the side adjacent over the length of the side opposite.

The secant of an angle is defined as the length of the hypotenuse over the length of the side adjacent.

The cosecant of an angle is defined as the length of the hypotenuse over the length of the side opposite.

4 0
3 years ago
What 124.2÷9 step-by-step explanation please help !! ( long division ..”
Andre45 [30]

Answer: 13.8

Step-by-step explanation:

5 0
3 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
(x^3 + 5)(2x – 1)<br>(x^2 – 4)(x^2 + 4)​
earnstyle [38]

Answer:

x^{3} +x^{2} +1

Step-by-step explanation:

5 0
3 years ago
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