It is always an acute angle, even if the angle was the minimum 1 degree the complement is still 89 degrees which is still acute
7k/3 = 21
x 3 x3
7k = 63
/7 /7
k = 9
(7(9)/3 = 21 = 63/3 = 21 = 21 = 21)
6 maybe? I used Siri sorry if it’s wrong
Answer:
16
Step-by-step explanation:
Restrictions for f and g: denominators can't be equal to zero.
1
• For f(x) = —— :
x²
x² ≠ 0
x ≠ 0
So the domain of f is
Dom(f) = {x ∈ R: x ≠ 0}
Dom(f) = R*
or using the interval notation,
Dom(f) = ]–∞, 0[ ∪ ]0, +∞[ .
________
5
• For g(x) = —— :
x²
Since g(x) = 5 · f(x), the restrictions for g are the same:
x² ≠ 0
x ≠ 0
So the domain of g is also
Dom(g) = {x ∈ R: x ≠ 0}
Dom(g) = R*
or using the interval notation,
Dom(g) = ]–∞, 0[ ∪ ]0, +∞[.
I hope this helps. =)
Tags: <em>function set domain restriction algebra</em>