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3 years ago

HELP find the values of x (see image)

Mathematics

2 answers:

klasskru [66]3 years ago

4 0

Answer:

4) 10

5) 15

6) 20

7) 4

8) 27

equations used to solve:

4) 4x+50=90

5) (2x+60)+6x=180

6) 3x+30=90

7) (8x+120)+7x=180

8) 99+3x=180

seropon [69]3 years ago

3 0

I don’t know I just have to answer this so I can search a question

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a retangle has an area of 6 square meters. what will be the area of the retangle if each side length is increased by a factor 5?

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3 years ago

The one selected is wrong please help meee!

GREYUIT [131]

Answer:

(a) ΔARS ≅ ΔAQT

Step-by-step explanation:

The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.

In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.

The desired congruence statement in Step 3 is ...

ΔARS ≅ ΔAQT

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2 years ago

Solve the following equation; domain 0< x < 360; 3 cot x + sqrt 3 = 0

kondaur [170]

ANSWER

$x =120 \degree \: or \: 300 \degree$

EXPLANATION

We want to solve the trigonometric equation

$3 \cot(x) + \sqrt{3} = 0$

We group like terms to obtain,

$3\cot(x) = - \sqrt{3}$

Divide both sides of the equation by 3 to get,

$\cot(x) = - \frac{ \sqrt{3} }{3}$

We can reciprocate both sides to get,

$\tan(x) = - \frac{3}{ \sqrt{3} }$

We simplify the right hand side to get,

$\tan(x) = - \sqrt{3}$

Since the tangent ratio is negative, it implies that it is either in the second quadrant or fourth quadrant.

In the second quadrant,

$x = 180 \degree - arctan( \sqrt{3})$

$x = 180 \degree - 60 \degree = 120 \degree$

In the fourth quadrant,

$x = 360 \degree - arctan( \sqrt{3})$

$x = 360 \degree - 60 \degree$

$x = 300 \degree$

6 0

4 years ago