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koban [17]
3 years ago
7

-5(y + 5) > 45 Answers y > -14 y > 4

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer: your correct  but the answer should be y<-14

Step-by-step explanation: i dont get the y>4 but if you solve -5(y + 5) > 45 you should get y<-14

hope this helped :)

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Solve for X: <br> 2.5x+12=32
Crank

Step-by-step explanation:

2.5x+12=32

We move all terms to the left:

2.5x+12-(32)=0

We add all the numbers together, and all the variables

2.5x-20=0

We move all terms containing x to the left, all other terms to the right

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Step-by-step explanation:

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3 years ago
Of is directly proportional toy and x = 45 when
kompoz [17]

Answer:

if x=ky, where k is constant.

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4 0
4 years ago
How to solve this :') please help
blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}

7 0
2 years ago
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