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topjm [15]
3 years ago
8

Abby bought an 8 pound bag of doog food for $7.40. How much does the bag cost per pound? (round to the nearest hundreth)

Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:

a

Step-by-step explanation:

kramer3 years ago
5 0

Answer:

0.92 per pound

Step-by-step explanation:

if you divide 7.40 from 8 it is 0.925. and if you multiply 0.925 by 8 it will give you 7.4. hope this helps.

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Subtract.<br> (11x2 + 3x – 9)-(2x2 + 2x + 7)
xeze [42]

Answer:

3

Step-by-step explanation:

Simplify: (-7x2 - 3x) - (4x2 - x) ... -11x2 – 2x ... 3x – 5 + 23x – 9 = 3x + 23x – 5 – 9 = 26x – 14 = 2(13x – 7) Answer: 2(13x – 7). 11 . ... 2x - 3 + 3 = - 9 + 3, (Adding 3 on both sides) 2x = -6 2x/2 = -6/2

3 0
3 years ago
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WILL GIVE BRAINLY NEED HELP BAD PLZ WUICK <br> What is the perimeter of the triangle?<br> units
AysviL [449]

Answer:

26units!

Step-by-step explanation:

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2 years ago
ONLY 1% OF PEOPLE GET THIS RIGHT AND One rabbit saw six elephants while he was going to the river. Each elephant saw two monkeys
Dvinal [7]

Answer:

31 animals

Step-by-step explanation:

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5 0
3 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
Which of the following can be added without altering any of the fractions?
Murrr4er [49]
<h3>Answer: Choice A</h3>

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\frac{A}{C}+\frac{B}{C} = \frac{A+B}{C}

We have numerators A and B added together over a common denominator C. If we didn't have a common denominator, then we'd have to do a bit of algebraic manipulation to get both fractions to a common denominator. It doesn't have to be the lowest common denominator (LCD), though it's often more efficient that way.

4 0
3 years ago
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