I will answer your question. It is -3/2
Answer: 7800
Step-by-step explanation:
As English alphabet has 26 letters.
So , Choices for First character in the code = 26
The choices for digits = 10 (From 0 to 9)
So , choices for second character = 10 (Middle two characters must be numbers)
choices for third character = 10 (Middle two characters must be numbers)
Choices for last character = 3 (the last character must be a 1, 3, or 7)
By Fundamental principle of counting , the total number of four character codes can be generated =
(Choices for First character)x (choices for digits) x(choices for digits) x(Choices for last character)
= (26) (10)(10)(3) =7800
Hence, the total number of character codes can be generated= 7800
Answer:
The best choice is y = 82.1
Step-by-step explanation:
Just simplify both sides of the equation, then isolate the variable.
Which makes it's exact form y= 34^5/4 and when converting it to decimal form it becomes y = 82.1
Answer:
Area of a circle=πr²
radius is half of the diameter
1/2×2=1
π1²
22/7×1
3.1415926535897932
~3.14
Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is
.
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is


Therefore, the probability is 0.35
Check the attached files for additionals