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liq [111]
3 years ago
14

The length of a rectangle is 5 in. More than 3 times its width. The quadratic function f(x) = x(3x + 5) represents the area of t

he rectangle in terms of its width. What is a reasonable domain of the function?
Mathematics
1 answer:
True [87]3 years ago
6 0

Answer: Domain of function is R^{ + } or (0, \infty )

Step-by-step explanation:

Assuming x as width of rectangle

so, Width = x

Question says, Length is 5in more than 3 times id width.

we write as Length = 3x+5

Therefore, Area of rectangle will be given function f(x)

f(x) = x(3x+5)

Here, It is important to notice that width and length of rectangle will always be positive values and also, area of rectangle is always positive.

we can write in equation as

x > 0

f(x) > 0

Thus, Domain of function is R^{ + } or (0, \infty )

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We can find the acceleration via

{v_f}^2-{v_i}^2=2a\Delta x

We have

\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)

\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}

Then by definition of average acceleration,

a_{\rm ave}=\dfrac{v_f-v_i}t

so that

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We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

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Then

\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2

\implies\boxed{t=6.33\,\mathrm s}

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