put a 1 under the 13, so it is 13/1, and 5 5/6, turn it into an improper fraction by multiplying 5x6=30. then 30+5, which is 35. so just keep the denominator, which would be 35/6. so you would have 13/1 - 35/6. you need the same denominator, so see what both 1 and 6 would fit into. which is 6. so 13x6 which is 78, so 78/6 - 35/6, so 78-35 is 43. so 43/6, then simplify, which is 7 1/6
1042 / 45
=23.15
You should be able to do that with a calculator though.
Answer:
# of 5 dollar bills: 9
# of 1 dollar bills: 6
Step-by-step explanation:
9•5 = 45
1•6 = 6
To Check: 45 + 6=51
Answer:
the answer to this complicated problem is 25
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417