How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your
1 answer:
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Answer: point F is at <u> 0.6 </u> on the number line
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Explanation:
The ratio 2:3 scales up to 2x:3x for some positive real number x.
This means the distance from D to F is 2x units, and the distance from F to E is 3x units. Combine those two smaller distances to get 2x+3x = 5x to represent the full distance from D to E.
D is at -3 and E is at 6. This is a distance of 9 units since |-3-6| = |-9| = 9
Set this equal to the 5x from earlier and solve
5x = 9
x = 9/5
x = 1.8
This leads to 2x = 2*1.8 = 3.6
Therefore, we'll move 3.6 units from -3 to -3+3.6 = 0.6 which is the location of point F on the number line.
Notice that from 0.6 to 6 is 5.4 units and that 3x = 3*1.8 = 5.4 matches up to help confirm the answer.
Answer:
≈ 20.8 ft
Step-by-step explanation:
A right triangle is formed between the wall, the ground and the ladder.
The ladder is the hypotenuse , the wall and ground are the legs.
let h be the height of the wall, then using Pythagoras' identity
h² + 33² = 39²
h² + 1089 = 1521 ( subtract 1089 from both sides )
h² = 432 ( take the square root of both sides )
h = ≈ 20.8 ft ( to the nearest tenth )