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IceJOKER [234]
3 years ago
8

Pls help me with this...

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0
1.25 thats the answer
xenn [34]3 years ago
7 0

Answer:

1.25 is the answer

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Hanna bought 28 roses. She divided them into a number of bunches. Each bunch had 7 roses.
nevsk [136]
Its (a) 28 ÷ b = 7 Because When we divide 28 roses in each bunch consisting 7 roses therefore there are 4 bunch of roses therefore the equation (a) satisfy the result and the variable b has value 4.  
8 0
3 years ago
Rae wants to poll the students in her school to find out their favorite subject.
Kipish [7]

Answer: It is B

Rae will ask 75 randomb students in her school

Step-by-step explanation:

honestly I just guessed, and got it right

8 0
3 years ago
Can someone please help me :) !!!!
Gwar [14]

Answer:

A

Step-by-step explanation:

supplementary angles add up to 180

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6 0
3 years ago
"Data from the World Health Organization in 2013 were used to predict the life expectancy of men in a country from the life expe
marshall27 [118]

Answer:

The predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

Step-by-step explanation:

The least square regression line is used to predict the value of the dependent variable from an independent variable.

The general form of a least square regression line is:

\hat y=\alpha +\beta x

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

The regression line to predict the life expectancy of men in a country from the life expectancy of women in that country is:

\hat y=3.73 +0.88 x

Compute the life expectancy of men in a country in which the life expectancy of women is 70 years as follows:

\hat y=3.73 +0.88 x

  =3.73 +(0.88\times 70)\\=3.73+61.6\\=65.33

Thus, the predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

6 0
4 years ago
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
3 years ago
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