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GenaCL600 [577]
3 years ago
11

Brennan ate 2 1/4 apples.Then he ate another 1 2/4 apples the next day.How many apples did Brennan eat altogether?Write in simpl

est.​
Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

UwU your welcome!

Step-by-step explanation:

Convert the mixed fractions to a decimal. 2 1/4 is 2.25 1 2/4 is 1.5 2. Add them up. 3. 3.75 as a decimal or 3 3/4 as a mixed fraction or 15/4 as a improper fraction.

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New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night (USA Today
Ierofanga [76]

Answer:

a) We can find the z score for the value of 225 and we got:

z = \frac{225-204}{55}=0.382

And we can find this probability with the complement rule:

P(z>0.382)=1-P(z

b) z = \frac{140-204}{55}=-1.164

And we can find this probability using the normal standard table or excel and we got:

P(z

c) P(200

And we can find this probability with this difference:

P(-0.072

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.072

d) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.2   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the costs of a population, and for this case we know the distribution for X is given by:

X \sim N(204,55)  

Where \mu=204 and \sigma=55

We are interested on this probability

P(X>225)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We can find the z score for the value of 225 and we got:

z = \frac{225-204}{55}=0.382

And we can find this probability with the complement rule:

P(z>0.382)=1-P(z

Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

z = \frac{140-204}{55}=-1.164

And we can find this probability using the normal standard table or excel and we got:

P(z

Part c

P(200

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(200

And we can find this probability with this difference:

P(-0.072

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.072

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.2   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

5 0
3 years ago
A weight-loss clinic advertised that last month its patients, on average,8lb lost . Assuming that average refers to the mean, wh
Ipatiy [6.2K]

Answer:

Given:

A weight-loss clinic advertised that last month its patients, on average, lost 8 lbs

Average refers to mean

a. Last month all of their patients lost at least 8 lbs.

Answer: Mean or average is a measure of central tendency or in other terms refers to the central value of the dataset. If the value of mean/average is 8lb, it signifies that there are some patients who have lost weights more than 8 lbs. So, this statement is False

b. Last month at least one of their patients lost exactly 8 lbs.

Answer: It is a possibility that all the patients have lost their weights greater than or less than 8 lbs. Since the mean is computed by summing up all the values (weight loss in this case) by the total number of observations, it is possible that there can be no patient who has lost exactly 8lbs. So, this statement is False.

c. Two months ago some of their patients lost at least 8 lbs.

Answer: It is clearly mentioned that last month its patients, on average, lost 8 lbs. No information is given about the weight loss of patients before the last month. So, there is not sufficient data to check whether this statement is correct or not.

d. Last month at least one of their patients lost less than 3 lbs.

Answer: It is a possibility that all the patients have lost their weights greater than 3 lbs. Since the mean is computed by summing up all the values (weight loss in this case) by the total number of observations, it is possible that there can be no patient who has lost less than 3lbs. So, this statement is False.

e. Last month, the number of their clients who lost less than 8 lbs was equal to the number of their clients who lost more than 8 lbs.

Answer: Mean is a measure of central tendency which is computed by the diving sum of all observations with the number of all observations (the sum of observations lesser than the mean is compensated by the sum of observations greater than the mean) and for the mean equal to 8lbs, there should be an equal number of people who lost less than 8 lbs and the number of people who lost more than 8 lbs. Hence, this statement is True.

Answer e.Last month, the number of their clients who lost less than 8 lbs was equal to the number of their clients who lost more than 8 lbs is True

7 0
2 years ago
Read 2 more answers
For which value of x is the equation 6 = 12x true?
skad [1K]

Answer:

x = 0.5

Step-by-step explanation:

5 0
3 years ago
Evaluate the formula V=B h over 3 for B=15 inches two squared and h=28inches?I WILL MARK AS BRAINLY
meriva
V=B/14-28...........
4 0
3 years ago
What percent of 20 is 16?!!!<br><br>What's the answer and how do I work the problem out?!!
-Dominant- [34]

<span>16/20 is 80%.</span>

You find out by multiplying the denominator: 20 * 5 = 100

Then, you do the same to the numerator which is: 16 * 5 = x

So, x = 80%

Hope this helps! :D

7 0
3 years ago
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