Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have

Computing the first derivative:

We find the critical points equating f'(x) to zero

Simplifying by -6

We get the critical points

They define the following intervals

Thus A=3 and B=6
Answer:
Answer:
g(x)=-6/5x+1/2
h(x)=-6/5x-1/2
Step-by-step explanation:
1). g(x)=−f(x) ?
f(x)=6/5x−1/2
g(x)=−(6/5x−1/2)
g(x)=-6/5x+1/2
2). h(x)=f(−x) ?
f(-x)=6/5(-x)−1/2
f(-x)=-6/5x-1/2
h(x)=-6/5x-1/2
Step-by-step explanation:
Plane #1 speed: x mph
Plane #2 speed: (x+30) mph
time = time becomes
170 mi 185 mi
---------- = --------------
x x+30
Solving for x, the speed of the slower plane, we get
170x + 5100 = 185 x
5100
Then 15x = 5100, and x = ---------- (mi/hr) = 340 mph
15
The slower plane flies at 340 mph, and the faster one at 370 mph.
Answer:
-1 I think sorry if its wrong
Answer:
8k+7
Step-by-step explanation:
Like terms!
5k+3k=8k