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k0ka [10]
3 years ago
12

Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many e

ggs as Mia. Pablo decides to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia?
Mathematics
1 answer:
andrezito [222]3 years ago
8 0
Pablo : 3(2x) = 6x
Sofia :  2x
Mia : x 

Assuming x = 10
Mia : x = 10
Sofia : 2x = 2(10) = 20
Pablo : 3(2x) = 3(20) = 60

10 + 20 + 60 = 90
90/3 = 30 candy eggs per person

Pablo: 60 x 1/2 = 30
Sophia: 30-20 = 10  : 10
Mia : 30 - 10 = 20 : 20

Ratio of eggs given to sophia from pablo's set = 10/60 = 1/6
Ratio of eggs given to mia from pablo's set = 20/60 = 2/6 = 1/3
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Suppose that a computer chip company has just shipped computer chips to a computer company.​ Unfortunately, of the chips are def
Varvara68 [4.7K]

Answer:

(a) 0.0000245

(b) 0.000025

Step-by-step explanation:

The complete question is:

Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 50 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) There are 50 defective chips out of 10,000 shipped. The probability that the first chip randomly selected is defective is  50 /10,000  = 0.005.  Compute the probability that two randomly selected chips are defective under the assumption of independent events.

Solution:

(a)

In this case we need to compute the conditional probability of selecting two defective chips, i.e. the selection of the second defective chip is dependent on the first defective chip.

The probability of selecting the first defective chip is:

P(1D)=\frac{50}{10000}=0.005

Now there are 9999 chips left and 49 defective chips among them.

The probability of selecting the second defective chip is:

P(2D)=\frac{49}{9999}=0.0049

Compute the probability that two randomly selected chips are defective using conditional probability as follows:

P (Two defective chips) =P(1D)\times P(2D)=0.005\times 0.0049=0.0000245

Thus, the answer is 0.0000245.

(b)

Compute the probability that two randomly selected chips are defective under the assumption of independent events as follows:

The above statement implies that the selection was done with replacement.

The probability is:

P (Two defective chips) =P(1D)\times P(2D)

                                      =\frac{50}{10000}\times \frac{50}{10000}\\\\=0.005\times 0.005\\\\=0.000025

Thus, the probability that two randomly selected chips are defective under the assumption of independent events is 0.000025.

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3 years ago
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julia-pushkina [17]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
10×10×25= show your work please
zalisa [80]
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