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4 years ago

Solve the equation by finding square roots x^2 + 8x + 16 =9

Mathematics

1 answer:

Mashcka [7]4 years ago

7 0

The left side can be condensed as a squared binomial:

$x^2+8x+16=(x+4)^2=9\implies x+4=\pm\sqrt9\implies x+4=\pm3$

$\implies\boxed{x=-1\text{ or }x=-7}$

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Step-by-step explanation:

When solving for the principal we still need to use the formula $A = P(1+\dfrac{r}{n})^{nt}$ .

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Now we can substitute the values and solve for the principal.

$A=P(1+\dfrac{r}{n})^{nt}$

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$\dfrac{4369.20}{1.05919912849}=\dfrac{P(1.05919912849)}{1.05919912849}$

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To check for our answer, we can simply substitute the values including the principal and excluding the total.

$A=P(1+\dfrac{r}{n})^{nt}$

$A=4125(1+\dfrac{0.033}{4})^{4(1.75)}$

$A=4125(1+0.00825)^{7}$

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3 years ago

Solve the equation by finding square roots x^2 + 8x + 16 =9​

Solve the equation by finding square roots x^2 + 8x + 16 =9