Answer:
x=2
Step-by-step explanation:
If 3x + y = 7, then y= 7 - 3x.
Substitute in x - 2y = 0
So:
x - 2(7-3x)=0
x-14+6x=0
7x=14
x=2
Plug in the point for each equation:
x=1/4y + a
(1)=1/4(2) + a
1=1/2+a
1/2=a
y=1/4x+b
2=1/4(1) +b
b= 7/4
Solve a+b:
a+b=?
(2/4)+(7/4)= 9/4= 2.25
By applying the definition of logarithm, you have
![\log_x(64) = 3 \iff x^3 = 64](https://tex.z-dn.net/?f=%20%5Clog_x%2864%29%20%3D%203%20%5Ciff%20x%5E3%20%3D%2064%20)
So, if you consider the cubic root of both sides, you have
![x = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%20x%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%3D%204%20)
Answer:
false
Step-by-step explanation:
because
-3(x-5)
-3x+15
For 12 < 3b lets solve it:
12/3 < b
b > 4
For 2b + 14 < 4 lets solve it:
2b < 4 - 14
2b < -10
b < -10/2
b < -5