A standard deck of playing cards consists of 52 playing cards.
1. Count the probability of drawing two aces from a standard deck without replacment.
Among 52 playing cards are 4 aces, then the probability to select first ace is 4/52=1/13. After picking out first ace, only 3 aces left and in total 51 playing cards left, then the probability to select second ace is 3/51=1/17. Use the product rule to find the probability to select two aces without replacement:

2. Count the probability of drawing two aces from a standard deck with replacment.
Among 52 playing cards are 4 aces, then the probability to select first ace is 4/52=1/13. After picking out first ace, this card was returned back into the deck and the probability to select second ace is 4/52=1/13 too. Use the product rule to find the probability to select two aces with replacement:

3. If events A and B are independent, then 
All these three steps show you that the first card was replaced and events are independent.
When u got a + in the middle, parenthesis are not needed
3x^2 - 2 + 2x^2 - 6x + 3...now we combine like terms
5x^2 - 6x + 1 <==
S^5 + 10s^4v + 40s^3v^2 +80s^2 v^3 +80sv^4 +32v^5
Composite numbers more than 2 numbers can go into it like 4 numbers that can go into 4 are 1,2,4
<span>Step 1 :</span><span>Simplify 13y2-5yx - 23x2</span><span>
1.1 </span> Factoring <span> 13y2 - 5yx - 8x2</span> Try to factor this multi-variable trinomial using trial and error<span> </span>Found a factorization : (y - x)•(13y + 8x)
Final result :<span> (y - x) • (13y + 8x)</span>