We're not supposed to help with exams. This isn't an exam, is it?
A(0)=202, A(37)=half that.
Last choice.
I need help it khan 4q+3+2q-1
1 answer:
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Sinθ=opposite side/hypotenuse
cosθ=adjacent side/hypotenuse
where both the sides are relative to theta.
in this case, 22 is your hypotenuse. theta (θ) is the angle you are examining. i've included a diagram for reference because the equations may format differently depending on which angle you choose as theta.
using my diagram:
sinθ = o/h
sin 15 = o/22
sin 15(22) = o
o=5.69m/s
therefore the vertical component is about 5.69m/s.
cosθ=a/h
cos15 = a/22
cos15(22) = a
a = 21.25m/s
therefore, your horizontal component is about 21.25m/s.
cosθ=adjacent side/hypotenuse
where both the sides are relative to theta.
in this case, 22 is your hypotenuse. theta (θ) is the angle you are examining. i've included a diagram for reference because the equations may format differently depending on which angle you choose as theta.
using my diagram:
sinθ = o/h
sin 15 = o/22
sin 15(22) = o
o=5.69m/s
therefore the vertical component is about 5.69m/s.
cosθ=a/h
cos15 = a/22
cos15(22) = a
a = 21.25m/s
therefore, your horizontal component is about 21.25m/s.