I need help it khan 4q+3+2q-1

Y=-6x+15 Y=4x-15 solve by elimination

Nikitich [7]

X=3 and y=−3 is the answer

6 0

3 years ago

Isabella has a 22 ounce cola. She drinks 17 ounces. Enter the percentage of ounces Isabella has left of her cola. Round your ans

jenyasd209 [6]

Answer:

22.73% of ounces Isabella has left of her cola.

Step-by-step explanation:

Given:

Isabella has a 22 ounce cola. She drinks 17 ounces.

Now, to find the percentage of ounces Isabella has left of her cola.

Total ounces of cola = 22.

Ounces of cola Isabella drink = 17.

So, the ounces of cola she left:

Total ounces of cola - ounces of cola Isabella drink.

$=22-17$

$=5\ ounces.$

Thus, 5 ounces of cola she left.

Now, to get the percentage of cola she left:

$\frac{5}{22}\times 100$

$=\frac{500}{22}$

$=22.727\%.$

Rounding the percentage to the nearest hundredths is 22.73%.

Therefore, 22.73% of ounces Isabella has left of her cola.

7 0

3 years ago

Suppose the lifetime of a cell phone battery is normally distributed with a mean of 36 months and a standard deviation of 2 mont

solong [7]

Answer:

They should guarantee the lifetime of their batteries for 32 months.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 36 months and a standard deviation of 2 months.

This means that $\mu = 36, \sigma = 2$