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2 years ago

HELP ME OUT PLEASE!!!

Mathematics

2 answers:

Vikki [24]2 years ago

6 0

Answer:

So the scale factor would be the length of the new rectangle divided by the length of the corresponding side for the original rectangle. So the scale factor is 1/2. Note: If you're going from a bigger shape to a smaller one, you know that the scale factor must be less than 1.

Step-by-step explanation:

otez555 [7]2 years ago

5 0

ANSWER:

STEP BY STEP EXPLANATION:

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Solve the question below, please.

Ne4ueva [31]

Answer:

Adam: 52.26°

Step-by-step explanation:

Use Cosine Rule, $Cos(C) = \frac{a^2 + b^2 - c^2}{2ab}$ , to find the angle of both players.

✔️Angle of Carlos:

Let the angle be C,

a = 50 ft

b = 40 ft

c = 24 ft

Plug in the values into the equation

$Cos(C) = \frac{50^2 + 40^2 - 24^2}{2*50*40}$

$Cos(C) = \frac{3,524}{4,000}$

$C = Cos^{-1}(\frac{3,524}{4,000})$

C = 28.24° (nearest hundredth)

✔️Angle of Adam:

Let the angle be C,

a = 30 ft

b = 22 ft

c = 24 ft

Plug in the values into the equation

$Cos(C) = \frac{30^2 + 22^2 - 24^2}{2*30*22}$

$Cos(C) = \frac{808}{1,320}$

$C = Cos^{-1}(\frac{808}{1,320)}$

C = 52.26° (nearest hundredth)

6 0

2 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

5 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIEST<br> PLS DUE TOMORROW <br> 9/27/18

s2008m [1.1K]

30. is 8 [-5] [3] [-2] -2

4 0

3 years ago

Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe

icang [17]

Answer:

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

h(-1) = 8(-1)²(-1-3) = -32

h(0) = 8(0)(0-3) = 0

h(2) = 8(2²)(2 -3) = -32

h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0

2 years ago

Please help me with the answer ASAP

AleksandrR [38]

Answer:

g(x) is greater

Step-by-step explanation:

it is greater because when mulitplying the function g and x you get a higher number than you would with f(x)

hope that helps!!

5 0

2 years ago