<span>[ (1 / 36) - (1 / x²) ] / [ (1 / 6) + (1 / x) ]
[ (x² - 36) / 36x² ] / [ (x + 6) / 6x ]
</span>remember that<span>:
x² - 36 = (x + 6)(x - 6)
so
[ (x+6)(x-6) / 36x² ] / [ (x + 6) / 6x ]
[ (x+6)(x-6) / 36x² ] * [ 6x / (x + 6) ]
6x / 36x² = 1 / 6x
[ (x+6)(x-6) / 6x ] * [ 1 / (x+6) ] -------------------- > </span>(x - 6) / 6x<span>
The answer is </span>(x - 6) / 6x<span>
</span>
Answer: One solution
Step-by-step explanation:
y = 3x + 3
y = -2x + 3
-----------------------------------------------------------------------------------------------------------
To solve this, you need to understand a few things:
a) If two lines have the same slope but different y-intercepts, they are parallel when graphed and thus do not have any solutions
b) If two lines have the same slope and same y-intercepts, they are the same line when graphed and thus do not have infinitely many solutions
c) If two lines have different slopes (and/or y-intercepts), they have one solution
-----------------------------------------------------------------------------------------------------------
These two lines have different slopes but the same y-intercept (condition c)
So they have one solution
Answer:
<h2>
![\frac{w}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bw%7D%7B3%7D)
</h2>
Step-by-step explanation:
Rewrite the division as a fraction.
Answer:
3135
Step-by-step explanation:
Givens
a1 = 6
Use t4 - t3 to get d
t4 = 27
t3 = 20
Step One
Find a1 and d
a1 = 6
d = t4 - t3
d = 27 - 20
d = 7
Step Two
Find the 30th Term
tn= a1 + (n -1 )*d
t30 = 6 + (30 - 1) * 7
t30 = 6 + 29*7
t30 = 6 + 203
t30 = 209
Step Three
Find the sum using Sum = (a + t30)*n/2
n = 30 given
a1 = 6 given
t30 = 209 calculated from step 2
Sum = (a1 + t30)*n/2 Substitute
Sum = (6+ 209)*30/2 Combine like terms and divide by 2
sum = 215 * 15 Multiply
Sum = 3135 Answer