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denis23 [38]
4 years ago
7

What is the minimum value for h(x)=x2−16x+60?

Mathematics
1 answer:
iogann1982 [59]4 years ago
3 0
Minimum value is equal to x=8, y=-4
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value. 
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