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4 years ago

What is the minimum value for h(x)=x2−16x+60?

1 answer:

iogann1982 [59]4 years ago

3 0

Minimum value is equal to x=8, y=-4
First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16
at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.
Just plug in 8 to the original equation to find the answer for the minimum value.

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3 years ago

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“ write the equation of the line that goes through the point (6,3) and is parallel to y=-2/3x+5 “ ????

brilliants [131]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

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