Answer: That used to happen to me but if you answer peoples questions it doesnt do that anymore because you are helping out
Step-by-step explanation:
Answer: In my opinion you could just shorten the number of orders so that it's not so long.
Explanation: The numbers can be from every 20 orders so 900, 920, 940...so on.
Answer:
The options are not shown, so i will answer in a general way.
Let's define the variables:
h = number of hats
m = number of mugs.
We know that a total of 1000 items were ordered, then:
h + m = 1000
We also know that we have 3 times more mugs than hats, this can be written as:
m = 3*h
Now we have the system of equations:
h + m = 1000
m = 3*h
To solve these, we usually start by isolating one of the variables in one equation and then replace that in the other equation, but in this case, we already have m isolated in the second equation, then we can replace that in the first equation to get:
h + m = 1000
h + (3*h) = 1000
Now we can solve this equation for h, and find the number of hats ordered.
4*h = 1000
h = 1000/4 = 250
There were 250 hats ordered.
<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)
2) Angles ABC and CDE are right angles (perpendicular lines form right angles)
3) Angles ABC and CDE are equal (all right angles are equal)
4) Angles ACB and DCE are equal (vertical angles are equal)
5) Triangles ABC and EDC are congruent (ASA)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
6) AB = DE (corresponding parts of congruent triangles are equal)
Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3
Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.
selection B is appropriate.
