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borishaifa [10]
3 years ago
8

With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the

mean number of servings of fruit claimed per day from the histogram. first use the information in the histogram to compute the sum of the 74 observations, and then use this to compute the mean.

Mathematics
1 answer:
coldgirl [10]3 years ago
4 0

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

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We discovered that 650 GSS respondents in 2006 watched television for an average of 2.98 hrs/day, with a standard deviation of 2
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a) 2.09167

b) 0.2

c) 130 correspondents

d) 5.38 hours per day

e) 69%

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 2.98hrs/day, Standard Deviation = 2.4

a) What is the Z score for a person who watches more than 8 hrs/day.

z = 8 - 2.98/2.4

= 2.09167

b) What proportion of people watch 5 hrs/day or more television?

z = 5 - 2.98/2.4

z = 0.84167

Determining the Probabilityvalue from Z-Table:

P(x<5) = 0.80001

The proportion of people watch 5 hrs/day or more television

P(x>5) = 1 - P(x<5) = 0.19999

Approximately = 0.2

c) How many does this correspond to in the sample?

From the question above, we are told that: there are 650 GSS respondents in 2006 watched television

Hence the proportion that corresponds to Question b is

0.2 × 650

= 130 correspondents

Therefore, 130 correspondents watch 5 hrs a day or more television

d) What number of television hours per day corresponds to a Z = +1.

z score formula is given as:

z = (x-μ)/σ

Z = +1

x = unknown

Mean = 2.98

Standard deviation = 2.4

Hence:

1 = x - 2.98/2.4

Cross Multiply

1 × 2.4 = x - 2.98

2.4 = x - 2.98

2.4 + 2.98 + x

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e)What is the percentage of people who watch between 1 and 6 hours of television per day?

For x = 1

z = 1 - 2.98/2.4

z = -0.825

Probability value from Z-Table:

P(x= 1) = 0.20469

For x = 6

z = 6 - 2.98/2.4

z = 1.25833

Probability value from Z-Table:

P(x = 6) = 0.89586

The percentage of people who watch between 1 and 6 hours of television per day is calculated as:

P(x = 6) - P(x = 1)

0.89586 - 0.20469

= 0.69117

Converting to percentage,

0.69117 × 100%

= 69.117%

To the nearest whole number = 69%

Therefore, 69% of the people who watch between 1 and 6 hours of television per day

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