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antiseptic1488 [7]
3 years ago
5

At a local print shop, 14 copies can be made for $4. At this rate, how much would it cost to make 63 copies?

Mathematics
2 answers:
Illusion [34]3 years ago
7 0
It would cost 18$ ! hope this helps :)
Alex17521 [72]3 years ago
7 0
18 , because you would count by 14 but when you get to 56 your gonna have to do halve then add 7 that equals 63 then your gonna have to could by 4’s 4,8,12,16 so then halve of 4 is 2 so 18
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the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small
Orlov [11]

C1/C2 =  2/3

 2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

8 0
3 years ago
Read 2 more answers
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
Jamie is investing $47,000 in an account paying 9.26% interest compounded continuously. What will Jamie's account balance be in
frutty [35]

Answer:

7398740

Step-by-step explanation:

17*9.26=157.42

please give me brainliest

47,000 *157.42

7398740

5 0
3 years ago
What kind of triangle is this!!! Please Help!!!
Arisa [49]

Answer:

Right Isosceles

Step-by-step explanation:

First, let's see if this triangle is Acute, Obtuse or Right.

We see that PB and QB are perpendicular lines, meaning that they form a right angle.  Therefore, triangle PQB is a right triangle.

Next, let's see if this triangle is equilateral, isosceles or scalene. PB and QB are congruent side lengths but PQ is not congruent to either PB or QB. Therefore, because two of the side lengths are congruent to each other and one is not, then triangle PQB is a isosceles triangle.

In conclusion, triangle PQB can be categorized as a right isosceles triangle.

Hope this helps!

3 0
3 years ago
A total of $12,000 is invested in two corporate bonds that pay 7.5% and 9% simple interest. The invest wants an annual interest
nlexa [21]

Answer:

$13,200

Step-by-step explanation:

You need to use the simple interest formula

I = P * r * t

I = Interest accrued

P = Principal amount invested

r = Interest rate          you need to divide by 100 to get it in decimal form

t = time, in years        if you are given a partial year, divide the months by 12

P = $12,000                                    

r = 7.5% = .075                                    

t = 1                                                  

But, because we want I to equal $990 then I is

I = $990

So we ignore our P and instead solve for the P that will give us the desired result.

I = P * r * t

$990 = P * .075 * 1

$990 = P.075        Divide each side by .075

$990/.075 = P.075/.075

$990/.075 = P

$13,200 = P

So, to earn an annual interest income of $990, $13,200 will have to be invested in the 7.5% bond.

6 0
3 years ago
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