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otez555 [7]
3 years ago
7

What is the area i need help

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

the formula of a trapezoid is

H(a+b/2)

A= side 1 (usually the two parallel sides, choose one)

b= side 2 (same thing as A but the second line)

The h is height

So we fot 10 and 9

10+9=19

19/2=9.5

9.5*6

57

the Area is 57

Also you drew it wrong (look at image)

Ray Of Light [21]3 years ago
8 0
The area is 57 i believe i’m not to sure though
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Please help me for my homework
Citrus2011 [14]

Answer:

m<CAO = 56

Step-by-step explanation:

When two parallel lines are intersected by a transversal, the same-side interior angles are supplementary, meaning that their angle measures add up to (180) degrees. Using this information, substitute in the given values and solve for the unknown,

(m<DOA) + (m<CAO) = 180

Substitute,

3x + 40 + 2x = 180

Simplify,

5x + 40 = 180

Inverse operations,

5x + 40 = 180

     -40    -40

5x = 140

/5     /5

x = 28

Now substitute the value of (x) back into the given expression for the value of (<CAO). Solve to find the numerical value.

<CAO = (2x)

= 2(28)

= 56

4 0
3 years ago
??? I really dont understand this i keep getting it wrong someone plzz help im tryna graduate
Drupady [299]

Hello!

There are two ways to address this problem. The most efficient way is to solve for u. Another way is to substitute the values from the first column of the table into the given equation, 1 - 5u > -44, solve, and then determine if the side of the left is greater than the right side.

Solving for u:

1 - 5u > -44 (subtract 1 from both sides)

-5u > -45 (divide both sides by -5)

u < 9

Notice that the inequality sign is flipped. If you divide by a negative number, the inequality sign has to flip the other way. < → >, > → <, ≤ → ≥, or ≥ → ≤.

Since u is less than 9, any numbers less than 9 make this equation true.

1. 10 < 9, this is not a solution.

2. 9 < 9, this is not a solution.

3. -10 < 9, this is a solution.

4. 7 < 9, this is a solution.

Substitution Method:

When u = 10, 1 - 5(10) > -44

1 - 50 > -44

-49 > -44 | u = 10 is not a solution.

When u = 9, 1 - 5(9) > -44

1 - 45 > -44

-44 > -44 | u = 9 is not a solution.

When u = -10, 1 - 5(-10) > -44

1 + 50 > -44

51 > -44 | u = -10 is a solution.

When u = 7, 1 - 5(7) > -44

1 - 35 > -44

-34 > -44 | u = 7 is a solution.

As seen above, using both methods can achieve the same solution. So therefore, the answer is no, no, yes, and yes.

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