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2 years ago

Simplify this expression.

Mathematics

2 answers:

olchik [2.2K]2 years ago

7 0

Answer:

(y^2+3y-28)/(4y^2-15y-4)

Step-by-step explanation:

(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)

= (y+7)(y-3)/(y-4)(4y+1)

= (y^2+3y-28)/(4y^2-15y-4)

ANEK [815]2 years ago

6 0

Answer:

(y+7)/(4y+1).

Step-by-step explanation:

If we factor all the polynomials we get:

(4y-1)(y-3) . (2y+3)(y+3) . (y-4)(y+7)

-------------- ---------------- -------------

(2y+3)(y-4) (4y-1)(4y+1) (y-3)(y+3)

we see that (4y-1), (y -3), (2y+3), (y+3) and (y - 4) are in the numerators and denominators so we can cancel them out.

This leaves us with:

(y + 7)

--------

(4y + 1)

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Determine the best method to solve the system of equations. Then solve the system.

maxonik [38]

Answer:

x=1 y = -1/2

(1,-1/2)

Step-by-step explanation:

7x-2y=8

5x+2y=4

I would use elimination since we have 2y in one equation and -2y in the other

7x-2y=8

5x+2y=4

--------------------

12x = 12

Divide each side by 12

12x/12 = 12/12

x =1

The substitute back into equation 2

5(1) +2y = 4

5 +2y = 4

Subtract 5

5-5+2y = 4-5

2y = -1

Divide by 2

2y/2 = -1/2

y = -1/2

8 0

3 years ago

Read 2 more answers

In a line of students. Jenna is number 8. The teacher says that a rule for a number patter is add 4. The first student in line s

tatyana61 [14]

She says 35 because number 7 in line says 31, so 31+4=35...

I hope this helped you!

7 0

3 years ago

Which of the following constants can be added to x2 + x to form a perfect square trinomial?

solmaris [256]

The constant should be added to form a perfect square trinomial will be 1/4. Then the correct option is D.

<h3>What is a quadratic equation?</h3>

It's a polynomial with a value of zero. There exist polynomials of variable power 2, 1, and 0 terms. A quadratic equation is an equation with one statement in which the degree of the parameter is a maximum of 2.

The expression is x² + x.

Then the constant should be added to form a perfect square trinomial.

Then the constant will be

The square of the half of the coefficient of the variable x is to be added to make a perfect square.

Then the constant will be 1/4.

Then the perfect square will be

$\rm \rightarrow x^2 + x + \dfrac{1}{4}\\\\\\\rightarrow x^2 + 2 \times \dfrac{1}{2} x + \left (\dfrac{1}{2} \right )^2\\\\\\\rightarrow \left (x + \dfrac{1}{2} \right)^2$