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2 years ago

Simplify this expression.

Mathematics

2 answers:

olchik [2.2K]2 years ago

7 0

Answer:

(y^2+3y-28)/(4y^2-15y-4)

Step-by-step explanation:

(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)

= (y+7)(y-3)/(y-4)(4y+1)

= (y^2+3y-28)/(4y^2-15y-4)

ANEK [815]2 years ago

6 0

Answer:

(y+7)/(4y+1).

Step-by-step explanation:

If we factor all the polynomials we get:

(4y-1)(y-3) . (2y+3)(y+3) . (y-4)(y+7)

-------------- ---------------- -------------

(2y+3)(y-4) (4y-1)(4y+1) (y-3)(y+3)

we see that (4y-1), (y -3), (2y+3), (y+3) and (y - 4) are in the numerators and denominators so we can cancel them out.

This leaves us with:

(y + 7)

--------

(4y + 1)

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