Answer:
-16 sqrt(3) +16i
Step-by-step explanation:
z = 2 cis (pi/6)
z^5 = 2^5 cis (5*pi/6)
z^5 = 32 cis (5pi/6)
z^5 = 32 cos (5pi/6) + 32 i sin (5pi/6)
= 32 * (-sqrt(3)/2) + 32i (1/2)
= -16 sqrt(3) +16i
X<1/2y y=10(x-1)
is my reading on this.
So the first equation is x is less than one half y
second equation is y is 10 times x less 1
Were there options to choose from?
Option e is the answer I think
