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Varvara68 [4.7K]
3 years ago
7

For f (x) = 2x+1 and g(x) = x2 - 7, find (fºg)(2).

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

Step-by-step explanation:

Your first step will be to set up the problem:

f(x) - g(x)

Next you will substitute in your values:

(2x + 1) - (x2 - 7)

The easiest way to do the subtraction problems is to distribute your negative into your second set of parenthesis, so your expression would become:

2x + 1 - x2 + 7

Then combine your like terms:

2x - x2 + 8

Lastly put your expression in standard form (highest exponent to lowest)

-x2 + 2x + 8

Hope this helped!

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weqwewe [10]
Substitution property
7 0
3 years ago
I need help asap! With formula and explanation please!
Lorico [155]

Answer:

Base: 5

Exponent: 4

Step-by-step explanation:

Base is the large number in the formula and Exponent is the little number above the large number lol

Hope this helps!

8 0
2 years ago
For an integer n ≥ 0, show that (n/2) - (-n/2) = n.<br><br> Use greatest integer function
mars1129 [50]

The greatest integer function returns the largest integer smaller than the number you provide it. That is, if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is an integer, then the "greatest integer of <em>x</em>" is [<em>x</em>] = <em>n</em>.

• Let <em>n</em> be even. Then we can write <em>n</em> = 2<em>k</em> for some integer <em>k</em> ≥ 0. Now,

[<em>n</em>/2] = [<em>k</em>] = <em>k</em>

while

[-<em>n</em>/2] = [-<em>k</em>] = -<em>k</em>

so that

[<em>n</em>/2] - [-<em>n</em>/2] = 2<em>k</em> = <em>n</em>

<em />

• Let <em>n</em> be odd. Then <em>n</em> = 2<em>k</em> + 1 for some integer <em>k</em> ≥ 0. Every odd integer occurs between two even integers, so that

<em>n</em> - 1 < <em>n</em> < <em>n</em> + 1

or equivalently,

2<em>k</em> < <em>n</em> < 2<em>k</em> + 2

so that

<em>k</em> < <em>n</em>/2 < <em>k</em> + 1

It follows that [<em>n</em>/2] = <em>k</em>.

Similarly, if we negative the previous inequality, we have

-<em>k</em> > -<em>n</em>/2 > -(<em>k</em> + 1), or -<em>k</em> - 1 < -<em>n</em>/2 < -<em>k</em>

which means [-<em>n</em>/2] = -<em>k</em> - 1.

So we make the same conclusion,

[<em>n</em>/2] - [-<em>n</em>/2] = <em>k</em> - (-<em>k</em> - 1) = 2<em>k</em> + 1 = <em>n</em>

3 0
2 years ago
Solve −x16+1≥−5x2, for x without multiplying by a negative number. Then, solve by multiplying through by −16.
dedylja [7]

Answer:

−1.13348172≤x≤1.13348172

Step-by-step explanation:

For this problem

Add −5x2 to both sides of the inequality.

−x16 + 1 + 5x2≥0

Convert inequality to an equation.

−x16 + 1 + 5x2 = 0

Factor −x16 + 1 + 5x2

Set the factor equal to 00.

x16−5x2−1 = 0

x≈ − 1.13348172,1.13348172

so,

x≤ − 1,13348172

−1.13348172≤x≤1.13348172

x≥1.13348172

−1.13348172≤x≤1.13348172

7 0
3 years ago
What is the quotient?
Sergio039 [100]

Answer: FIRST OPTION

Step-by-step explanation:

According the quotient of powers property, when you have the division of two powers with the same base, then you must subtract the exponents.

Therefore, keeping the property above on mind, you have that the quotient is the shown below:

\frac{(-7)^2}{(-7)^{-1}}=(-7)^{(2-(-1))}=(-7)^{(2+1)}=(-7)^3=-343

6 0
3 years ago
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