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Dmitriy789 [7]
3 years ago
13

Draw a model for a fraction1/6

Mathematics
2 answers:
Papessa [141]3 years ago
7 0

Answer: I can't draw it but i answered

Step-by-step explanation:

To draw a model for 1/6 you would have draw six shapes of any kind. Then you would only fill one of them.

zepelin [54]3 years ago
5 0

Answer:

Step-by-step explanation:

picture to help

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Write each decimal as a fraction <br> .07<br> .051<br> .473<br> .27<br> .5.37<br> .16.49
Colt1911 [192]

Answer:

7/10

51/100

473/1000

27/100

537/1000

1649/10000

Step-by-step explanation:

im curious about what the dots are in .16.49 and .5.37, why are there two dots?

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2 years ago
Which story problem is solved using multiplication? Answer options with 5 options
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D is the answer because it says each and that’s a key word to understand that it’s multiplying
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PLEASE HELP!!!! IMA DESPRATE!!!!!!!!Find the second term in the sequence defined by an = −5(n2 + 1n).
Dmitrij [34]

The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20

<h3>How to find the nth term of a sequence?</h3>

We are given the formula for a sequence as;

aₙ = -5(n² + 1n)

Where n is the position of the term.

Now, for the first term, we will have;

a₁ = -5(1² + 1(1))

a₁ = -10

The second term of the sequence is;

a₂ = -5(2² + 1(2))

a₂ = -20

Read more about Sequence at; brainly.com/question/6561461

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2 years ago
F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?
SVEN [57.7K]

Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

Function is F(t)=t^2+19+60

Zeroes of the function are

t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

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makkiz [27]

the answer is C :)))

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