Answer:
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 29.5
Standard deviation r = 5.2
Number of samples n = 59
Confidence interval = 90%
z-value (at 90% confidence) = 1.645
Substituting the values we have;
29.5+/-1.645(5.2/√59)
29.5+/-1.645(0.676982337100)
29.5+/-1.113635944529
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
Check the attachment below. Answer: 5/2
The length of ST is 10 units, the length of S't" is 2 units.
This means the dilated figure was decreased by a factor of 5.
Because it is smaller it would be a scale factor of 1/5 ( 0.2 as a decimal).
15% of 1560 is 234. 234/0.15=1560 and 1560 x 0.15=234, therefore the answer is 1560.
Step-by-step explanation:
Did you mean :
f(x) = 5(4 - x)
f(16) = 5(4 - 16)
f(16) = 5(-12)
f(16) = -60
