1. Place your compass point on X and measure the distance to point Y. Swing an arc of this size above (or below) the segment.
2. Without changing the span on the compass, place the compass point on Y and swing the same arc, intersecting with the first arc.
3. Label the point of intersection as the third vertex of the equilateral triangle.
4. Use you straight edge and connect the points.
Answer:
Step-by-step explanation:
Both expression are the same :
14 = 2(x + 3)
By expansion :
14 = 2*x + 2*3
14 = 2x + 6
Hence ;
Both expression are the same
Weight of one circle :
Final weight on both sides are equal:
Weight on Left hand side = 14
Weight on right hand side = 3*x + 3*x
Weight on Left hand side = Weight on right hand side
14 = 3x + 3x
14 = 6x
x = 14 / 6
x = 2.333
Answer:
I think the answers is B
Step-by-step explanation:
But im so sorry if its not right...
<em>H</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>n</em><em>i</em><em>c</em><em>e</em><em> </em><em>d</em><em>a</em><em>y</em>
Answer:
it would be the second answer because the shape has to get 3/4 smaller than the pre-image
Step-by-step explanation:
Step-by-step explanation:
Note that since 
we can see from the figure that 
and 
have the same measure.
a) To solve for the length of 
we write
b) Since the two triangles are congruent, we can say that 
so we can write
Solving for y, we get
