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Nadusha1986 [10]
3 years ago
15

Find the value of x please help

Mathematics
2 answers:
Tema [17]3 years ago
7 0

Answer:

Angles in a triangle are sum up to 180 degrees.

35 + 110 + (x+12)=180

145+x+12=180

157+x=180

x=180-157

x=23 degrees

____ [38]3 years ago
3 0

using angle sum property

we get

110+35+(x+12)=180

(x+12)=180-145

(x+12)= 35

x= 35-12

x= 23

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Find the sum of 1727 and 1415
pishuonlain [190]

Answer:

3142

Step-by-step explanation:

1727 + 1415 = 3142

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WHAT VALUE COMES AFTER TEN THOUSANDS
Mrac [35]
Hundreds thousands comes after. Hope that helps!
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4 years ago
(4x-3/2x+1)-10(2x+1/4x-3)=3
agasfer [191]

Step-by-step explanation:

4x-3x/2+1)-10(2x+1/4x-3)=3

4x-3x/2+1-20x+5/2x-3=3

collect like terms

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B20%7D%20" id="TexFormula1" title=" \sqrt{20} " alt=" \sqrt{20} " align="absmiddle
tester [92]
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8 0
4 years ago
Find the P-value for a test of the claim that more than 60% of the people following a particular diet will experience increased
lina2011 [118]

Answer:

The p-value of the test is 0.0207.

Step-by-step explanation:

Test of the claim that more than 60% of the people following a particular diet will experience increased energy (H1: p > 0.6).

The null hypothesis is:

H_0: p = 0.6

The alternate hypothesis is:

H_1: p > 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that \mu = 0.6, \sigma = \sqrt{0.6*0.4}

Of 100 randomly selected subjects who followed the diet, 70 noticed an increase in their energy level.

This means that n = 100, X = \frac{70}{100} = 0.7

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.7 - 0.6}{\frac{\\sqrt{0.6*0.4}}{\sqrt{100}}}

z = 2.04

P-value of the test:

The p-value of the test is the probability of finding a sample proportion of at least 0.7, which is 1 subtracted by the p-value of z = 2.04.

Looking at the z-table, z = 2.04 has a p-value of 0.9793

1 - 0.9793 = 0.0207

The p-value of the test is 0.0207.

4 0
3 years ago
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