3.75 pounds in 60 ounces. :)
Answer:
a) Binomial distribution B(n=12,p=0.01)
b) P=0.007
c) P=0.999924
d) P=0.366
Step-by-step explanation:
a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.
b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

Then,

c) In this case, the distribution is B(1200,0.01)

d) In this case, the distribution is B(100,0.01)
We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

Answer:
1/12
Step-by-step explanation:
dice rolling=1/6
coin flipping=1/2
Hence probability=1/6×1/2
Answer:
min-mid-max-mid-min
-cosine
Step-by-step explanation:
This is the correct answer, further proof in the file attached.
Answer:
B. 7/2, -8/3
Step-by-step explanation:
Move all the terms to the left side and set them equal to zero. Then set each factor equal to zero.