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Aleksandr [31]
2 years ago
6

On a six-question multiple-choice test there are five possible answers for each question, of which one is correct (C) and four a

re incorrect (I). If a student guesses randomly and independently, find the probability of being correct on two questions.
Mathematics
1 answer:
brilliants [131]2 years ago
8 0
Since the events are independent and can be reduced to two outcomes, we can solve it using the binomial formula.

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Please help will mark brainliest
Ivenika [448]

Answer:

It should be -64

Step-by-step explanation:

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2 years ago
I'm not sure where to start and how to differentiate this.
Mazyrski [523]
The picture is not clear. let me assume y = (x^4)ln(x^3)

product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)

dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)

look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
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... chain rule (in detail)

end up with
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5 0
3 years ago
Help me pleaseee I need help
MAVERICK [17]
I think it is b because probability of 2 is 1/6 then probability of 4 is 1/6. If you times them together 1/6x1/6 it will equal 1/36 so b
6 0
2 years ago
An olympic sprinter can run 56 yards in 8 seconds. At the same rate, how long (in seconds) would it take the sprinter to run 81
aniked [119]

Answer:

20,365.7 seconds

Step-by-step explanation:

First, we need to know how to convert yards to miles, as the question is in miles. We know that 1 mile is equivalent to 1760 yards. So we have:

1 mi = 1760 yards

If we multiply both sides by 81:

81 mi = 142,560‬ yards

And we know that the sprinter needs 8 second to run 56 yards:

8 s = 56 yards

If we divide both sides by 56 we get the time he needs for 1 yard:

8/56 s = 56/56 yards

1/7 s = 1 yard

So, takes him 1/7 seconds to run one yard. At this rate he runs 142,560 yards in:

(1/7) * 142,560 = 20,365.7

So, he needs 20,365.7 seconds to run 81 miles (142,560 yards)

6 0
3 years ago
How many eggs are there in 3 5/6 dozen?
uranmaximum [27]

Answer:

check your eggs

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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