Can I get help for number 17

Complete the solution of the equation. Find the

Gelneren [198K]

Answer:

y = -7

Step-by-step explanation:

If x equals -14 then you would plug it in and the equation would be -2(-14)-3y=49

The new equation would be 28-3y=49

Then you would subtract 28 from both sides and get -3y=21

Lastly you would divide both sides by -3 and get y=-7

3 0

3 years ago

For what values of b is the relation R:{(b^2, 5), (5b, 6)} NOT a function?

Roman55 [17]

Answer:

b=0,b=5

Step-by-step explanation:

3 0

2 years ago

A pattern of being late for or for appointments is usually

Marysya12 [62]

A pattern of being late for work or for appointments is usually DIRECTLY RELATED TO ONE'S PERSONALITY TYPE.

There are 16 personality types. These are the following:
1) the duty fulfiller - NOT LATE
2) the mechanic - MAY BE LATE
3) the nurturer - NOT LATE
4) the artist - NOT LATE
5) the protector - NOT LATE
6) the idealist - NOT LATE
7) the scientist - NOT LATE
8) the thinker - NOT LATE
9) the doer - MAY BE LATE
10) the guardian - NOT LATE
11) the performer - MAY BE LATE
12) the caregiver - NOT LATE
13) the inspirer - MAY BE LATE
14) the giver - NOT LATE
15) the visionary - MAY BE LATE
16) the executive - NOT LATE

4 0

3 years ago

How many zero pairs must be added to the function

ELEN [110]

In short, Your Answer would be Option D) 25

Hope this helps!

5 0

3 years ago

Read 2 more answers

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

3 years ago