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Andrej [43]
3 years ago
7

What equation is used to find the vertex form of a parabola with the vertex (h, k)?

Mathematics
2 answers:
makkiz [27]3 years ago
8 0

Answer:

y=a(x-h)^{2}+h

Step-by-step explanation:

equation for vertex form of a parabola is,

y=a(x-h)^{2}+h

Georgia [21]3 years ago
6 0

Answer:

y=a+h

Step-by-step explanation:

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Marnie practiced her basketball dribbling. After 2 tries she had bounced the ball 88 times. On the second try she had 2 fewer bo
Alina [70]
Ok! The first thing u have to do is multiply 2 times 88 which its 178 then u multiply 2 times 8 which it equals 16. Then u add 178+16 and it equals 194.
6 0
4 years ago
:
sergij07 [2.7K]

For this case we have the following arithmetic sequence:

a_ {n} = 15 + 5 (n-1)

To write in function form, we apply distributive property to the terms within parentheses:

f (n) = 15 + 5n-5

Different signs are subtracted and the major sign is placed.

We simplify:

f (n) = 5n + 10

Answer:

f (n) = 5n + 10

Option C

4 0
3 years ago
Choose a benchmark for each measurement. Use 0, 1/2, or 1
MrRissso [65]

Answer:

4/8

Step-by-step explanation:

it's equivalent to 1/2

7 0
3 years ago
Read 2 more answers
What is the vertex of the parabola? y + 4 = 1/2 (x - 7)^2<br>Please help fast !
Ber [7]
Get into form (x-h)^2=4p(y-k)
vetex is (h,k)

so
1/2(x-7)^2=y+4
times 2 both sides
(x-7)^2=2(y+4)
(x-7)^2=4(1/2)(y-(-4))
vertex is (7,-4)
8 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05
Dimas [21]

Answer:

the null and alternative hypothesis are

H_{0}: p=0.24

H_{a}: p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

<em>At 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

H_{0}: p=0.24

H_{a}: p≠0.24

test statistic can be calculated as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of yellow offspring peas (\frac{155}{155+430} =0.265
  • p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)
  • N is the sample size (585)

Test statistic is z=\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } } ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that <em>at 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0
3 years ago
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