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3 years ago

What equation is used to find the vertex form of a parabola with the vertex (h, k)?

Mathematics

2 answers:

makkiz [27]3 years ago

8 0

Answer:

y=a $(x-h)^{2}$ +h

Step-by-step explanation:

equation for vertex form of a parabola is,

y=a $(x-h)^{2}$ +h

Georgia [21]3 years ago

6 0

Answer:

y=a+h

Step-by-step explanation:

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Marnie practiced her basketball dribbling. After 2 tries she had bounced the ball 88 times. On the second try she had 2 fewer bo

Alina [70]

Ok! The first thing u have to do is multiply 2 times 88 which its 178 then u multiply 2 times 8 which it equals 16. Then u add 178+16 and it equals 194.

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4 years ago

sergij07 [2.7K]

For this case we have the following arithmetic sequence:

$a_ {n} = 15 + 5 (n-1)$

To write in function form, we apply distributive property to the terms within parentheses:

$f (n) = 15 + 5n-5$

Different signs are subtracted and the major sign is placed.

We simplify:

$f (n) = 5n + 10$

Answer:

$f (n) = 5n + 10$

Option C

4 0

3 years ago

Choose a benchmark for each measurement. Use 0, 1/2, or 1

MrRissso [65]

Answer:

4/8

Step-by-step explanation:

it's equivalent to 1/2

7 0

3 years ago

Read 2 more answers

What is the vertex of the parabola? y + 4 = 1/2 (x - 7)^2 Please help fast !

Ber [7]

Get into form (x-h)^2=4p(y-k)
vetex is (h,k)

so
1/2(x-7)^2=y+4
times 2 both sides
(x-7)^2=2(y+4)
(x-7)^2=4(1/2)(y-(-4))
vertex is (7,-4)

8 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 430 green peas and 155 yellow peas. Use a 0.05

Dimas [21]

Answer:

the null and alternative hypothesis are

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

Test statistic is 1.416.

P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level

At 0.05 significance we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

Step-by-step explanation:

Let p be the proportion of offspring peas will be yellow. Then,

$H_{0}$ : p=0.24

$H_{a}$ : p≠0.24

test statistic can be calculated as

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of yellow offspring peas ( $\frac{155}{155+430} =0.265$
p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)

N is the sample size (585)

Test statistic is z= $\frac{0.265-0.24}{\sqrt{\frac{0.24*0.76}{585} } }$ ≈ 1.416.

Using z-table, we can find that P-Value is 0.1568

We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05

We can conclude that at 0.05 significance we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)

6 0

3 years ago