Answer:
D. Ted expanded more power.
Explanation:
Given the following data;
For Ted.
Force = 10N
Height = 1.5m
Time = 1 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/1
Power = 15 Watts.
For Johnny.
Force = 10N
Height = 1.5m
Time = 2 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/2
Power = 7.5 Watts
Therefore, from the calculations we can deduce and conclude that Ted expanded more power.
Answer:
a) 1.67 m/s
b) 23kJ
Explanation:
We need to apply the linear momentum conservation formula, that states:

in this case:

the initital kinetic energy is:

and the final:

The energy lost is given by:

Answer:
B. fjords
explanation :
Fjords were created by glaciers. In the Earth's last ice age, glaciers covered just about everything. Glaciers move very slowly over time, and can greatly alter the landscape once they have moved through an area. This process is called glaciation.The fjords are one of the glaciers that existed in the past. They are one of the many glacial relief forms that can give us a insight into the size and power of the glaciers.
Complete question:
A block of solid lead sits on a flat, level surface. Lead has a density of 1.13 x 104 kg/m3. The mass of the block is 20.0 kg. The amount of surface area of the block in contact with the surface is 2.03*10^-2*m2, What is the average pressure (in Pa) exerted on the surface by the block? Pa
Answer:
The average pressure exerted on the surface by the block is 9655.17 Pa
Explanation:
Given;
density of the lead, ρ = 1.13 x 10⁴ kg/m³
mass of the lead block, m = 20 kg
surface area of the area of the block, A = 2.03 x 10⁻² m²
Determine the force exerted on the surface by the block due to its weight;
F = mg
F = 20 x 9.8
F = 196 N
Determine the pressure exerted on the surface by the block
P = F / A
where;
P is the pressure
P = 196 / (2.03 x 10⁻²)
P = 9655.17 N/m²
P = 9655.17 Pa
Therefore, the average pressure exerted on the surface by the block is 9655.17 Pa