Answer:
muscle
Explanation:
weight can also be added by muscle. not necessarily fat. so if you have a lot of muscle so that adds weight you can be very powerful but can mover very slow.
Answer:
e) 11 m/s
Explanation:
For a particle under the action of a conservative force, its mechanical energy at point 0 is must be equal to its mechanical energy at point 1:
![K_1+U_1=K_0+U_0\\\\\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(x_1)^2+(2.0\frac{J}{m^4})(x_1)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})(x_0)^2+(2.0\frac{J}{m^4})(x_0)^4]](https://tex.z-dn.net/?f=K_1%2BU_1%3DK_0%2BU_0%5C%5C%5C%5C%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%28x_1%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%28x_1%29%5E4%5D%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%28x_0%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%28x_0%29%5E4%5D)
In 
the speed is given, so 
and 
. Replacing:
![\frac{mv_1^2}{2}+[(8.0\frac{J}{m^2})(1m)^2+(2.0\frac{J}{m^4})(1m)^4]=\frac{mv_0^2}{2}+[(8.0\frac{J}{m^2})0^2+(2.0\frac{J}{m^4})(0)^4]\\\frac{mv_1^2}{2}+8.0J+2.0J=\frac{mv_0^2}{2}\\\frac{mv_0^2}{2}=\frac{mv_1^2}{2}+10J\\v_0=\sqrt{\frac{2}{m}(\frac{mv_1^2}{2}+10J)}\\v_0=\sqrt{\frac{2}{0.2kg}(\frac{(0.2kg)(5\frac{m}{s})^2}{2}+10J)}\\v_0=11.18\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%29%281m%29%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%281m%29%5E4%5D%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%2B%5B%288.0%5Cfrac%7BJ%7D%7Bm%5E2%7D%290%5E2%2B%282.0%5Cfrac%7BJ%7D%7Bm%5E4%7D%29%280%29%5E4%5D%5C%5C%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B8.0J%2B2.0J%3D%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%5C%5C%5Cfrac%7Bmv_0%5E2%7D%7B2%7D%3D%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B10J%5C%5Cv_0%3D%5Csqrt%7B%5Cfrac%7B2%7D%7Bm%7D%28%5Cfrac%7Bmv_1%5E2%7D%7B2%7D%2B10J%29%7D%5C%5Cv_0%3D%5Csqrt%7B%5Cfrac%7B2%7D%7B0.2kg%7D%28%5Cfrac%7B%280.2kg%29%285%5Cfrac%7Bm%7D%7Bs%7D%29%5E2%7D%7B2%7D%2B10J%29%7D%5C%5Cv_0%3D11.18%5Cfrac%7Bm%7D%7Bs%7D)
By definition;
M = fo/fe
Where,
M = Angular magnification
fo = Focal length of objective lens
fe = Focal length of eyepiece lens
From the information given;
M = 180/30 = 6
If the object's <em>velocity is constant</em> ... (it's speed isn't changing AND it's moving in a straight line) ... then the net force on the object is zero.<em> (D)</em>
Either there are no forces at all acting on the object, OR there are forces on it but they're 'balanced' ... when you add up all of their sizes and directions, they just exactly cancel each other out, and they have the SAME EFFECT on the object as if there were no forces at all.
