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irina1246 [14]
3 years ago
7

A mixture of hydrocarbons contains 34.8% heptane, C7H16, 10.1% nonane, C9H20, and 55.1% octane, C8H18. The mixture is combusted

in an excess of oxygen. What mass of CO2 is generated from the combustion of 17.0 kg
of the mixture?
:
Chemistry
1 answer:
Zinaida [17]3 years ago
3 0
<h3>Mass of CO₂ generated from the combustion : 14.277 kg</h3><h3>Further explanation</h3>

Mass Heptane : 0.348 x 17 = 5.916 kg

mass C in Heptane (MW=100.21 g/mol) :

\tt \dfrac{7.12}{100.21}\times 5.916=4.959~kg

Mass Nonane : 0.101 x 17 = 1.717 kg

mass C in Nonane (MW=128.2 g/mol) :

\tt \dfrac{9.12}{128.2}\times 1.717=1.446~kg

Mass Octane : 0.551 x 17 = 9.367 kg

mass C in Otane (MW=114.23 g/mol) :

\tt \dfrac{8.12}{114.23}\times 9.367=7.872~kg

Total mass produced :

4.959+1.446+7.872=14.277 kg

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From this we conclude that,

The number of electrons (n)  in the reaction are 3.

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The quantity of charge required for the reduction of 0.0423 mole of Cr^{3+} = 0.0423\times 3\times F=0.1269F=0.1269\times 96500C=12245.85C

Now we have to calculate the time taken.

We know that,

q=I\times t

t=\frac{q}{I}=\frac{12245.85C}{55.2A}=221.845s=3.69min

Thus, the time it take to plate out will be, 3.69 minutes.

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