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Tems11 [23]
2 years ago
10

Explain whether areas B and D show the same season.

Chemistry
1 answer:
torisob [31]2 years ago
4 0
They do not show the same season. one is faced a different part of the sun
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What happens to the influenza virus every 20-40 years, and why? What are the recent example(s)?
LenKa [72]

Answer:

The influenza virus is mutated every 20-40 years.

Explanation:

Large mutations occur every 20-40 years. This results in a new influenza virus to  which the human population has no protection. These large mutations are almost always followed by an influenza pandemic.

Hope this helps!

8 0
3 years ago
Chromium(III) oxide reacts with hydrogen sulphide gas to form chromium(III) sulphide and water. How many grams of hydrogen sulph
ahrayia [7]

Answer:

165.726 g.

Explanation:

  • For the balanced equation:

<em>Cr₂O₃ + 3H₂S → Cr₂S₃ + 3H₂O,</em>

It is clear that 1 mol of Cr₂O₃ and 3 mol of H₂S to produce 1 mol of Cr₂S₃ and 3 mol of H₂O.

  • Firstly, we need to calculate the no. of moles of 324.8 g of chromium(III) sulphide:

no. of moles of Cr₂S₃ = mass/molar mass = (324.8 g)/(200.19 g/mol) = 1.62 mol.

  • Now, we can find the "no. of grams" of H₂S are needed:

<u><em>Using cross multiplication:</em></u>

3 mol of H₂S produces → 1 mol of Cr₂S₃, from stichiometry.

??? mol of H₂S produces → 1.62 mol of Cr₂S₃.

∴ The no. of moles of H₂S are needed = (3 mol)(1.62 mol)/(1 mol) = 4.86 mol.

∴ The "no. of grams" of H₂S are needed = (no. of moles of H₂S)(molar mass of H₂S) = (4.86 mol)(34.1 g/mol) = 165.726 g.

7 0
3 years ago
Calculate the mass, in grams, of cucl2 (mw = 134.452 g/mol) required to prepare 250.0 ml of a 6.11 % w/v cu2 (mw = 63.546 g/mol)
Sever21 [200]

6.11% w/v of Cu2+ implies that 6.11 g of Cu2+ is present in 100 ml of the solution

therefore,  250 ml of the solution would have: 250 ml * 6.11 g/100 ml = 15.275 g

# moles of Cu2+ = 15.275 g/63.546 g mole-1 = 0.2404 moles

1 mole of CuCl2 contain 1 mole of Cu2+ ion

Hence, 0.2404 moles of Cu2+ would correspond to 0.2404 moles of CuCl2

Molar mass of CuCl2 = 134.452 g/mole

The mass of CuCl2 required = 0.2404 moles * 134.452 g/mole = 32.32 grams

6 0
3 years ago
luminum and oxygen react according to the following equation: 4Al(s) +3O2(g) --&gt; 2Al2O3(s) What mass of Al2O3, in grams, can
Slav-nsk [51]

Answer: 8.7 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.6g}{27g/mol}=0.17moles

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.

According to stoichiometry:

4 moles of aluminium give = 2 moles of Al_2O_3(s)

Thus 0.17 moles of aluminium give=\frac{2}{4}\times 0.17=0.085mol

Mass of Al_2O_3=moles\times {\text {molar mass}}=0.085\times 102g/mol=8.7g

Thus the mass of Al_2O_3(s)  is 8.7 grams

8 0
2 years ago
What are the transition metals
Valentin [98]
Theyre the big bunched up group in the middle of the periodic table
8 0
2 years ago
Read 2 more answers
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